Physics 1
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AP Physics 1: Algebra-Based — Cheatsheet

Formulas, exam-day tips, and key terms on one page.

Formulas & relationships

Displacement
Δx = x_f − x_i
Final minus initial. A negative result simply means motion in the negative direction, not "less than zero distance".
Average velocity
v_avg = Δx / Δt = (x_f − x_i) / (t_f − t_i)
Units: metres per second, m/s. The sign of v_avg is the sign of Δx.
Velocity–time (no Δx)
v = v₀ + at
Use when you have or want time but not displacement.
Position–time (no v)
Δx = v₀t + ½at²
The ½ is not optional — dropping it is the single most common kinematics mistake.
Timeless equation (no t)
v² = v₀² + 2aΔx
The rescue equation when time is neither given nor asked for.
Slope and area
slope of x–t = v · slope of v–t = a · area under v–t = Δx
Two different graphs, three different meanings — keep straight which graph you are reading.
Projectile equations (horizontal launch, taking down as +)
horizontal: Δx = v_x·t · vertical: Δy = ½g·t² · v_y = g·t
No acceleration horizontally (v_x constant); a = g ≈ 10 m/s² vertically.
Newton’s second law
ΣF = ma
ΣF is the vector sum of all forces (newtons, N). Solve component by component: ΣF_x = ma_x and ΣF_y = ma_y.
Weight
W = mg
g = 10 m/s² here (AP tables use 9.8). Weight is a force in newtons; it is never measured in kilograms.
Weight components on an incline (angle θ)
along incline: mg sinθ · perpendicular: mg cosθ
On a ramp, gravity splits into a part that pulls the object down the slope (mg sinθ) and a part pressing it into the surface (mg cosθ).
Friction force
f_k = μ_k N · f_s ≤ μ_s N
On flat ground with no vertical push, N = mg. Static friction is an inequality: it only reaches its maximum right at the verge of slipping.
Centripetal acceleration and force
a_c = v² / r · F_c = mv² / r
Both point toward the center of the circle. Doubling the speed quadruples both, because v is squared.
Newton’s law of universal gravitation
F = G·m₁·m₂ / r²
G = 6.67 × 10⁻¹¹ N·m²/kg². The force is an inverse-square law: triple the separation and the force drops to one-ninth.
Work
W = F·d·cosθ
θ is the angle between the force and the displacement. Force along the motion → cosθ = 1; opposite → cosθ = −1; perpendicular → cosθ = 0.
Work–energy theorem
W_net = ΔKE = ½mv_f² − ½mv_i²
The total work done by all forces equals the change in kinetic energy. Speeding up means positive net work; slowing down means negative.
Kinetic energy
KE = ½mv²
v is speed. The ½ and the square are both essential — dropping either is a common error.
Potential energy
PE_grav = mgh · PE_spring = ½kx²
h is height above your chosen reference; x is the spring’s stretch or compression from equilibrium.
Conservation of mechanical energy
KE_i + PE_i = KE_f + PE_f
Valid when no friction or drag removes energy. With friction, add the dissipated thermal energy to the final side.
Energy with friction
KE_i + PE_i = KE_f + PE_f + E_thermal
Friction converts mechanical energy to heat. Total energy is still conserved — it just leaves the mechanical account.
Power
P = W / t · P = F·v
Units: watts (W) = joules per second. Use W/t when you know the total work and time; use Fv when you know a steady force and speed.
Momentum
p = mv
A vector in kg·m/s. Its direction is the direction of motion; reverse the motion and the sign flips.
Impulse–momentum theorem
J = F·Δt = Δp = m·v_f − m·v_i
Impulse (N·s) equals the change in momentum. For a bounce, remember v_f and v_i point in opposite directions.
Conservation of momentum
m₁v₁ + m₂v₂ = m₁v₁′ + m₂v₂′
Total momentum before = total momentum after. Keep signs consistent: opposite directions get opposite signs.
Perfectly inelastic collision
m₁v₁ + m₂v₂ = (m₁ + m₂)·v′
The objects stick, so they share one final velocity v′. Solve for v′ by dividing the total momentum by the total mass.
Center of mass (two objects)
x_cm = (m₁x₁ + m₂x₂) / (m₁ + m₂)
A mass-weighted average of positions. Placing your origin at one mass simplifies the arithmetic.
Linear–angular link
v = rω · a_t = rα
r is the distance from the rotation axis. Angular quantities use radians; v and a_t come out in m/s and m/s².
Rotational kinematics (constant α)
ω = ω₀ + αt · θ = ω₀t + ½αt²
Identical in form to the linear equations, with θ→x, ω→v, α→a. Every trick you learned in kinematics carries over.
Torque
τ = r·F·sinθ
θ is the angle between the position vector r and the force. Maximum torque when θ = 90° (force perpendicular); zero when θ = 0° (force along r).
Rotational inertia and Newton’s second law
I_point = mr² · τ_net = Iα
I is measured in kg·m². Mass far from the axis raises I steeply because of the square on r.
Static equilibrium conditions
ΣF = 0 and Στ = 0
Both must hold. For a balanced beam this reduces to (clockwise torques) = (counterclockwise torques) about any chosen pivot.
Rotational and total kinetic energy
KE_rot = ½Iω² · KE_total = ½mv² + ½Iω²
For a rolling object, add both terms. Energy conservation from a height h then reads mgh = ½mv² + ½Iω².
Angular momentum
L = Iω · L_point = mvr
Units kg·m²/s. For a point mass on a circle, r is its distance from the axis. Angular momentum is a vector along the spin axis.
Conservation of angular momentum
I₁ω₁ = I₂ω₂
Valid when net external torque is zero. If I drops to half, ω doubles; if I doubles, ω halves.
Rolling condition
v = rω
Ties center speed to spin rate for rolling without slipping. Also a = rα for the accelerations.
Hooke’s law and spring period
F = −kx · T = 2π√(m/k)
k is in N/m. A stiffer spring (larger k) gives a shorter period; a heavier mass gives a longer one.
Pendulum period
T = 2π√(L / g)
L is the string length; g = 10 m/s². Mass and (small) amplitude do not appear — only length changes the period on a given planet.
Period, frequency, angular frequency
f = 1 / T · ω = 2πf = 2π / T
T in seconds, f in hertz (Hz), ω in rad/s. Doubling the frequency halves the period.
Energy in SHM
E_total = ½kA² = ½mv_max²
All potential at the extremes, all kinetic at equilibrium. Setting the two equal gives v_max = A√(k/m).
Density, pressure, and pressure with depth
ρ = m/V · P = F/A · P = P₀ + ρgh
ρgh is the gauge pressure — the extra pressure from a depth h of fluid. P₀ is the pressure at the surface (often atmospheric).
Buoyant force
F_b = ρ_fluid · V_displaced · g
Uses the *fluid’s* density and the volume of fluid pushed aside. For a fully submerged object, V_displaced equals the object’s own volume.
Continuity equation
A₁v₁ = A₂v₂
For incompressible, steady flow. Area and speed are inversely related: halve the area and the speed doubles.
Bernoulli’s equation
P + ½ρv² + ρgh = constant (along a streamline)
For flow at constant height the ρgh terms cancel, leaving P + ½ρv² constant — higher speed forces lower pressure.

On the exam

How to get a 5

Key terms

Kinematic equations (constant a)v = v₀ + at; x = x₀ + v₀t + ½at²; v² = v₀² + 2aΔx.
Newton's second lawΣF = ma. Acceleration is in the direction of net force; draw a free-body diagram first.
Weight vs massWeight (force) = mg in newtons, depends on g. Mass is amount of matter in kg, constant everywhere.
Work–energy theoremW_net = ΔKE = ½mv_f² − ½mv_i². Work = F·d·cosθ.
Conservation of mechanical energyOnly conservative forces: KE_i + PE_i = KE_f + PE_f. PE_grav = mgh; KE = ½mv².
Impulse–momentum theoremJ = FΔt = Δp = mΔv. Longer contact time reduces the force for a given Δp.
Elastic vs inelastic collisionBoth conserve momentum. Elastic conserves KE; inelastic does not. Perfectly inelastic → objects stick.
Centripetal acceleration and forcea_c = v²/r toward center; F_c = mv²/r. It is a net-force requirement, not a new force.
Hooke's law and spring PEF = −kx (restoring); elastic PE = ½kx². k = spring constant (N/m).
Conditions for static equilibriumΣF = 0 AND Στ = 0. Torque τ = rF sinθ.
SHM period (pendulum & spring)Pendulum: T = 2π√(L/g). Spring: T = 2π√(m/k). Period independent of amplitude.
Newton's third lawEqual and opposite forces act on DIFFERENT objects, so they never cancel on one object.