AP Physics 1: Algebra-Based — Cheatsheet
Formulas, exam-day tips, and key terms on one page.
Formulas & relationships
Displacement
Δx = x_f − x_i
Final minus initial. A negative result simply means motion in the negative direction, not "less than zero distance".
Average velocity
v_avg = Δx / Δt = (x_f − x_i) / (t_f − t_i)
Units: meters per second, m/s. The sign of v_avg is the sign of Δx.
Velocity–time (no Δx)
v = v₀ + at
Use when you have or want time but not displacement.
Position–time (no v)
Δx = v₀t + ½at²
The ½ is not optional — dropping it is the single most common kinematics mistake.
Timeless equation (no t)
v² = v₀² + 2aΔx
The rescue equation when time is neither given nor asked for.
Slope and area
slope of x–t = v · slope of v–t = a · area under v–t = Δx
Two different graphs, three different meanings — keep straight which graph you are reading.
Projectile equations (horizontal launch, taking down as +)
horizontal: Δx = v_x·t · vertical: Δy = ½g·t² · v_y = g·t
No acceleration horizontally (v_x constant); a = g ≈ 10 m/s² vertically.
Newton’s second law
ΣF = ma
ΣF is the vector sum of all forces (newtons, N). Solve component by component: ΣF_x = ma_x and ΣF_y = ma_y.
Weight
W = mg
g = 10 m/s² here (AP tables use 9.8). Weight is a force in newtons; it is never measured in kilograms.
Weight components on an incline (angle θ)
along incline: mg sinθ · perpendicular: mg cosθ
On a ramp, gravity splits into a part that pulls the object down the slope (mg sinθ) and a part pressing it into the surface (mg cosθ).
Friction force
f_k = μ_k N · f_s ≤ μ_s N
On flat ground with no vertical push, N = mg. Static friction is an inequality: it only reaches its maximum right at the verge of slipping.
Centripetal acceleration and force
a_c = v² / r · F_c = mv² / r
Both point toward the center of the circle. Doubling the speed quadruples both, because v is squared.
Newton’s law of universal gravitation
F = G·m₁·m₂ / r²
G = 6.67 × 10⁻¹¹ N·m²/kg². The force is an inverse-square law: triple the separation and the force drops to one-ninth.
Work
W = F·d·cosθ
θ is the angle between the force and the displacement. Force along the motion → cosθ = 1; opposite → cosθ = −1; perpendicular → cosθ = 0.
Work–energy theorem
W_net = ΔKE = ½mv_f² − ½mv_i²
The total work done by all forces equals the change in kinetic energy. Speeding up means positive net work; slowing down means negative.
Kinetic energy
KE = ½mv²
v is speed. The ½ and the square are both essential — dropping either is a common error.
Potential energy
PE_grav = mgh · PE_spring = ½kx²
h is height above your chosen reference; x is the spring’s stretch or compression from equilibrium.
Conservation of mechanical energy
KE_i + PE_i = KE_f + PE_f
Valid when no friction or drag removes energy. With friction, add the dissipated thermal energy to the final side.
Energy with friction
KE_i + PE_i = KE_f + PE_f + E_thermal
Friction converts mechanical energy to heat. Total energy is still conserved — it just leaves the mechanical account.
Power
P = W / t · P = F·v
Units: watts (W) = joules per second. Use W/t when you know the total work and time; use Fv when you know a steady force and speed.
Momentum
p = mv
A vector in kg·m/s. Its direction is the direction of motion; reverse the motion and the sign flips.
Impulse–momentum theorem
J = F·Δt = Δp = m·v_f − m·v_i
Impulse (N·s) equals the change in momentum. For a bounce, remember v_f and v_i point in opposite directions.
Conservation of momentum
m₁v₁ + m₂v₂ = m₁v₁′ + m₂v₂′
Total momentum before = total momentum after. Keep signs consistent: opposite directions get opposite signs.
Perfectly inelastic collision
m₁v₁ + m₂v₂ = (m₁ + m₂)·v′
The objects stick, so they share one final velocity v′. Solve for v′ by dividing the total momentum by the total mass.
Center of mass (two objects)
x_cm = (m₁x₁ + m₂x₂) / (m₁ + m₂)
A mass-weighted average of positions. Placing your origin at one mass simplifies the arithmetic.
Linear–angular link
v = rω · a_t = rα
r is the distance from the rotation axis. Angular quantities use radians; v and a_t come out in m/s and m/s².
Rotational kinematics (constant α)
ω = ω₀ + αt · θ = ω₀t + ½αt²
Identical in form to the linear equations, with θ→x, ω→v, α→a. Every trick you learned in kinematics carries over.
Torque
τ = r·F·sinθ
θ is the angle between the position vector r and the force. Maximum torque when θ = 90° (force perpendicular); zero when θ = 0° (force along r).
Rotational inertia and Newton’s second law
I_point = mr² · τ_net = Iα
I is measured in kg·m². Mass far from the axis raises I steeply because of the square on r.
Static equilibrium conditions
ΣF = 0 and Στ = 0
Both must hold. For a balanced beam this reduces to (clockwise torques) = (counterclockwise torques) about any chosen pivot.
Rotational and total kinetic energy
KE_rot = ½Iω² · KE_total = ½mv² + ½Iω²
For a rolling object, add both terms. Energy conservation from a height h then reads mgh = ½mv² + ½Iω².
Angular momentum
L = Iω · L_point = mvr
Units kg·m²/s. For a point mass on a circle, r is its distance from the axis. Angular momentum is a vector along the spin axis.
Conservation of angular momentum
I₁ω₁ = I₂ω₂
Valid when net external torque is zero. If I drops to half, ω doubles; if I doubles, ω halves.
Rolling condition
v = rω
Ties center speed to spin rate for rolling without slipping. Also a = rα for the accelerations.
Hooke’s law and spring period
F = −kx · T = 2π√(m/k)
k is in N/m. A stiffer spring (larger k) gives a shorter period; a heavier mass gives a longer one.
Pendulum period
T = 2π√(L / g)
L is the string length; g = 10 m/s². Mass and (small) amplitude do not appear — only length changes the period on a given planet.
Period, frequency, angular frequency
f = 1 / T · ω = 2πf = 2π / T
T in seconds, f in hertz (Hz), ω in rad/s. Doubling the frequency halves the period.
Energy in SHM
E_total = ½kA² = ½mv_max²
All potential at the extremes, all kinetic at equilibrium. Setting the two equal gives v_max = A√(k/m).
Density, pressure, and pressure with depth
ρ = m/V · P = F/A · P = P₀ + ρgh
ρgh is the gauge pressure — the extra pressure from a depth h of fluid. P₀ is the pressure at the surface (often atmospheric).
Buoyant force
F_b = ρ_fluid · V_displaced · g
Uses the *fluid’s* density and the volume of fluid pushed aside. For a fully submerged object, V_displaced equals the object’s own volume.
Continuity equation
A₁v₁ = A₂v₂
For incompressible, steady flow. Area and speed are inversely related: halve the area and the speed doubles.
Bernoulli’s equation
P + ½ρv² + ρgh = constant (along a streamline)
For flow at constant height the ρgh terms cancel, leaving P + ½ρv² constant — higher speed forces lower pressure.
The translation chain
slope of x–t = v · slope of v–t = a · area under a–t = Δv · area under v–t = Δx
Slopes going down, areas going up. Area below the time axis is negative in both directions.
Angled projectile setup
v₀ₓ = v₀ cos θ · v₀ᵧ = v₀ sin θ · x: Δx = v₀ₓt · y: Δy = v₀ᵧt − ½gt², vᵧ = v₀ᵧ − gt
Taking up as positive, so g enters with a minus sign. Flipping that convention is fine as long as you flip it everywhere.
Range on level ground
R = v₀² sin(2θ) / g
Only valid when landing height equals launch height. sin(2θ) peaks at 2θ = 90°, i.e. θ = 45°.
The two-step method
Step 1 (system): a = ΣF_external / Σm · Step 2 (one body): ΣF on that body = m_that body · a
Step 1 gives the acceleration. Step 2 uses that acceleration to solve for the internal force.
Block on a frictionless incline
along: mg sin θ = ma → a = g sin θ · perpendicular: N = mg cos θ
The acceleration down a frictionless incline is independent of mass — the same reason all objects fall together.
Newton's second law for circular motion
ΣF_toward center = m v² / r
Sum the *real* forces, taking toward-the-center as positive. Then set that sum equal to mv²/r.
Circular orbit
GMm/r² = mv²/r → v = √(GM/r) · T = 2π√(r³/GM)
The orbiting mass m cancels: orbital speed and period depend only on the central mass and the radius, never on the satellite.
Energy accounting
W_external = ΔK + ΔU + ΔE_thermal
Everything crossing the boundary on the left; everything stored or dissipated inside on the right.
Work from a graph
W = area under the F-vs-x curve · For a spring: W = ½kx² (the triangle under F = kx)
The ½ in the spring energy is not a separate rule — it is the area of the triangle under a straight line through the origin.
Force from a potential-energy curve
F = −dU/dx (the negative slope)
The minus sign means force always points *downhill* on the U curve, toward lower potential energy.
Two-dimensional conservation
Σm v_x before = Σm v_x after · Σm v_y before = Σm v_y after
Two separate scalar equations. Recombine with |p| = √(pₓ² + pᵧ²) and θ = tan⁻¹(pᵧ/pₓ).
Which law applies
ALL collisions: momentum conserved · ELASTIC only: kinetic energy also conserved
Momentum is the reliable one. Kinetic energy is the special case, so never assume it.
Rotational inertia
I = Σ m r² (units kg·m²)
r is measured from the axis of rotation, not from the center of mass, unless the two coincide.
Newton's second law for rotation
Στ = I α
Torque plays the role of force, rotational inertia the role of mass, angular acceleration the role of acceleration.
Static equilibrium
ΣF_x = 0 · ΣF_y = 0 · Στ = 0 about ANY point
The torque condition holds about every point when the body is in equilibrium, which is what makes the pivot a free choice.
Rolling without slipping
v_cm = ωR · a_cm = αR · distance traveled = Rθ
Only valid when there is no slipping. A spinning wheel on ice violates all three.
Total kinetic energy of a rolling object
K = ½mv² + ½Iω² and with I = cmR² plus ω = v/R: K = ½(1 + c) mv²
c is the shape coefficient: 2/5 for a solid sphere, ½ for a disk, 1 for a hoop.
Conservation of angular momentum
I₁ω₁ = I₂ω₂ (when Στ_external = 0)
Reduce I and ω must rise to compensate. This is the entire content of the skater, diver and neutron-star examples.
Angular impulse–momentum theorem
τ Δt = ΔL = I ω_f − I ω_i
The exact analogue of F Δt = Δp. For a varying torque, the angular impulse is the area under a torque–time graph.
The defining relation
F = −kx → a = −(k/m)x
The minus sign is the physics: force and acceleration always point back toward equilibrium, opposite the displacement.
Maxima in SHM
v_max = ωA = A√(k/m) · a_max = ω²A = (k/m)A
Both scale with amplitude, which is why a wider swing is both faster at the bottom and harder pulled at the ends.
Periods
Spring: T = 2π√(m/k) · Pendulum: T = 2π√(L/g)
Spring period depends on mass but not g; pendulum period depends on g but not mass. Exactly reversed.
Archimedes' principle
F_b = ρ_fluid · V_displaced · g
V_displaced is the submerged volume, which equals the object's total volume only when it is fully underwater.
Continuity equation
A₁v₁ = A₂v₂, with A = πr² for a circular pipe
Volume per second is conserved. Halving the radius quadruples the speed, not doubles it.
Bernoulli's equation
P + ½ρv² + ρgh = constant along a streamline
Pressure work + kinetic energy + potential energy, each per unit volume. Every term has units of pascals.
On the exam
- On the AP exam, always state your positive direction before plugging in numbers. Half of kinematics is bookkeeping — a consistent sign convention earns points that raw algebra cannot.
- When a problem gives you velocities and a distance but never mentions time, reach straight for v² = v₀² + 2aΔx. Recognizing that missing variable saves you from solving a needless quadratic.
- Free-response graph questions love the chain "slope of x–t → v, slope of v–t → a, area under v–t → Δx". Memorize those three links and you can convert between any pair of graphs.
- The classic AP trap: applying gravity to the horizontal axis. Horizontal velocity is constant for every projectile. Gravity changes only the vertical velocity. Keep the two axes in separate columns on your paper.
- On the AP exam, "equilibrium" does not mean "at rest." An object moving at constant velocity has zero acceleration, so its net force is also zero. Constant velocity and rest are the *same* dynamical situation.
- Draw the free-body diagram before writing a single equation. On free response, a correct FBD with properly labeled forces earns points even if your algebra later slips — and it prevents you from inventing forces that are not there.
- Watch the difference between "is it moving yet?" and "how fast does it slow down?" Use **static** friction (an inequality, up to μ_s N) to test whether motion starts; use **kinetic** friction (a fixed μ_k N) once it is already sliding.
- When a circular-motion problem asks for a force, first ask "which real force points toward the center?" Then set that force equal to mv²/r. Naming the actual force (tension, friction, gravity, normal) is what earns the reasoning point.
- Before computing work, check the angle between the force and the displacement. Perpendicular forces (normal force on a flat surface, gravity in horizontal motion, tension in circular motion) do exactly zero work — a favorite AP trap.
- You may place the h = 0 reference wherever it is most convenient — the floor, the tabletop, the ground below a cliff. Only the *change* in height between start and finish affects the physics, so choose the level that makes the arithmetic simplest.
- If a problem mentions friction or air resistance, mechanical energy is *not* conserved — the "missing" energy became heat. Write KE_i + PE_i = KE_f + PE_f + E_thermal and treat the thermal term as the energy removed.
- Remember that power and energy are different quantities: energy (joules) is the total transferred, power (watts) is the rate. A question asking "how quickly" or "per second" is about power; "how much total" is about energy or work.
- When asked why a safety feature reduces force, argue from J = FΔt with Δp fixed. The impulse (momentum change) is set by the collision, so a longer Δt forces a smaller F. Name the theorem to earn the reasoning point.
- For any "at rest, then flies apart" problem, set total momentum equal to zero. The pieces carry equal and opposite momenta, so the mass ratio is the inverse of the speed ratio — heavier means slower.
- Two equations, two situations: momentum conservation works for *every* collision, but the kinetic-energy conservation equation is only valid for collisions the problem calls elastic. Never assume energy is conserved unless told so.
- Internal forces never move the center of mass. Whenever a problem shows an object breaking apart or flexing with no external force, the CM keeps whatever motion it had — a fast way to reason about explosions and recoil.
- Watch the difference between angular speed ω (shared by the whole object) and linear speed v (larger the farther you are from the axis). A question about "a point on the rim" almost always wants v = rω, not ω.
- When a force is not perpendicular, do not forget the sinθ. A common error is using τ = rF and ignoring the angle; only the perpendicular component turns the object.
- On the AP formula sheet you are given I for standard shapes (hoop MR², solid disk ½MR², sphere ⅖MR²). You are not expected to derive them — just choose the right one and remember the pattern: mass farther out gives a bigger coefficient.
- Free-response equilibrium problems almost always need both conditions. Write ΣF = 0 and Στ = 0 as two separate equations — many setups are unsolvable from the force equation alone.
- In a "race down the ramp" question, the object that puts *less* energy into rotation (smaller I relative to mR²) ends up moving faster. That is a direct consequence of splitting mgh between ½mv² and ½Iω².
- Angular momentum is a vector along the rotation axis. On the AP exam its direction matters most in conservation problems, where the total vector — magnitude and direction — must stay constant.
- Conservation of angular momentum needs zero *external* torque. Internal changes — pulling in arms, dropping on clay — do not violate it. Check that nothing outside the system is applying a torque before you set L constant.
- For ramp-race questions, rank shapes by how much of mgh goes into rotation: sphere (⅖MR²) beats disk (½MR²) beats hoop (MR²). Mass and radius cancel out, so the *shape* alone decides the winner.
- A frequent SHM question asks "where is acceleration maximum / speed maximum?" Remember they are opposite: acceleration peaks at the extremes (max force), speed peaks at equilibrium (max KE).
- To change a pendulum’s period you must change its length or move it to a different g. Adding mass or (for small swings) changing the amplitude does nothing — a common distractor on the exam.
- Keep the units straight: period is seconds *per* cycle, frequency is cycles *per* second. When a problem gives "cycles in a time," divide cycles by time for frequency, then invert for period.
- The total energy of an oscillator scales with the *square* of the amplitude (E = ½kA²). Double the amplitude and you quadruple the energy — and the maximum speed only doubles, since v_max scales linearly with A.
- Distinguish gauge pressure (ρgh, the pressure from the fluid alone) from absolute pressure (P₀ + ρgh, which adds the atmosphere on top). Read the question carefully to see which is asked.
- For a floating object, the buoyant force exactly equals its weight (it is in equilibrium). The fraction submerged equals the ratio of the object’s density to the fluid’s density — a handy shortcut for iceberg-style problems.
- Continuity assumes an incompressible fluid and steady flow. On the AP exam it is almost always paired with Bernoulli’s equation: first use continuity to get the speeds, then feed them into Bernoulli for the pressures.
- Solve fluid-flow free-response in two steps: continuity (A₁v₁ = A₂v₂) gives the speeds, then Bernoulli (P + ½ρv² + ρgh = constant) gives the pressures. For horizontal pipes, drop the ρgh terms to simplify.
- If a free-response part says "the students plot the data so that the graph is linear", it is asking you to rearrange the equation into y = mx + b and name the axes. State what goes on each axis *and* what the slope represents — both are separate rubric points.
- Write "up is positive" at the top of any projectile free-response and use it consistently. Rubrics award the sign convention, and a single flipped sign in the vertical equation usually propagates into every later part of the question.
- Draw a separate free-body diagram for each object, even when you plan to use the system shortcut. Rubrics award the diagrams independently of the algebra, and a labeled diagram with no numbers still earns points.
- On any circular-motion free-response, write "toward the center is positive" and then sum only the real forces. If your equation contains a term called F_c alongside tension and weight, you have counted the same force twice.
- On a free-response, state your system and your zero of potential energy in words before writing any equation. Both are rubric points on energy questions, and choosing the ground as U = 0 makes almost every problem arithmetically cleaner.
- When a graph question gives a force in newtons and a position axis in centimeters, convert before computing the area. Unit slips on graph-area questions are more common than conceptual errors, and the rubric does not distinguish between the two.
- Draw and label a before/after sketch with your axes marked before writing anything. On two-dimensional momentum free-responses, the two component equations are separate rubric points, and setting them up correctly earns credit even if the arithmetic goes wrong.
- When a free-response has a collision followed by a swing, slide or rise, it almost always wants momentum for the collision and energy for what follows. Using energy through the collision itself is the single most common way students lose the whole question.
- The AP equation sheet gives you the rotational inertia coefficients, so do not memorize them — but do learn their *order* (sphere < disk < hoop). Ranking questions ask which object wins a race or needs more torque, and the ranking alone answers them.
- State your pivot explicitly and label the sign convention (counterclockwise positive is standard). Rubrics award the correct torque equation, and an equation with an unstated pivot cannot be graded even when the numbers are right.
- Whenever a problem says "rolls without slipping", write v = ωR and a = αR immediately. That constraint is the equation that closes the system, and rubrics award it as a separate point from the dynamics equations it connects.
- A "which arrives first" ranking task is answered entirely by the rotational inertia coefficient. Say that the object with the smaller coefficient devotes a smaller fraction of its energy to rotation and therefore has more translational speed — that reasoning is the rubric point, not the number.
- Say "no net external torque acts about the axis, so angular momentum is conserved" in words before writing I₁ω₁ = I₂ω₂. Naming the condition is a rubric point independent of the algebra, and it forces you to check whether the condition actually holds.
- For a collision that then leads to a swing, write two clearly separated stages on your paper: "Stage 1, collision — angular momentum" and "Stage 2, swing — energy". Rubrics score the two stages independently, so a correct stage 2 still earns points even after a slip in stage 1.
- Graph questions often supply one curve and ask you to sketch another. Mark the moments where the given curve is zero and where it peaks, then use the rule that peaks in one graph line up with zeros in the next. Sketching from those anchor points is far more reliable than trying to draw a sinusoid freehand.
- Experimental-design questions want a *procedure*, not just an equation: name the quantity you vary, the quantities you hold constant, the instrument you use, and what you plot. Each of those is typically its own rubric point, and they can be earned even if the final calculation goes wrong.
- On buoyancy free-responses, start by drawing a free-body diagram with weight down and buoyant force up, plus tension or a normal force if present. Every buoyancy question in this unit is a force balance, and the diagram earns its own rubric point.
- Check that every term in a Bernoulli equation comes out in pascals before you solve. P, ½ρv² and ρgh must all have the same units, and a term that does not is the fastest way to catch a substitution error under time pressure.
How to get a 5
- Always draw a labeled free-body diagram before equations — it's often worth points and prevents sign errors.
- For the paragraph response, write complete sentences with physics vocabulary and cite the principle (e.g., "by conservation of momentum") — bullet fragments lose credit.
- Start from a fundamental principle and derive symbolically before plugging in numbers; the exam rewards the correct relationship even if arithmetic fails.
- When justifying, connect to a conservation law or Newton's laws explicitly and address the specific scenario — explain WHY, don't restate the answer.
- Draw the free-body diagram before writing any equation and label each force by its physical agent (Earth, surface, string). Invented forces such as “centrifugal force” or “force of motion” lose points immediately on the AP scoring guidelines.
- On “justify your answer” and paragraph-length response parts, name a specific principle (Newton’s third law, conservation of angular momentum, the work–energy theorem) and tie it to the given numbers or graph. Restating the answer in different words earns nothing.
- Solve symbolically first, then substitute. A symbolic result such as h = Us/(mg) instantly answers the “what if the mass doubles?” follow-up and earns partial credit even if the arithmetic later slips.
- For experimental design questions, name the equipment, state what you measure and how many trials, and say how you would linearize the data (plot T² against m, not T against m). Then explain what the slope means physically.
- Expect proportional reasoning on the multiple-choice section: fields obey inverse squares (double r → quarter g), kinetic and spring energies go as the square (double v → quadruple K), and pipe speeds scale with area rather than radius.
Key terms
Kinematic equations (constant a) — v = v₀ + at; x = x₀ + v₀t + ½at²; v² = v₀² + 2aΔx.
Newton's second law — ΣF = ma, applied separately along each axis. Acceleration is in the direction of the NET force, not of any single force.
Weight vs mass — Mass is the amount of matter and is frame-independent; weight is the gravitational force mg and changes with location.
Work–energy theorem — W_net = ΔK = ½mv_f² − ½mv_i². The net work done on an object equals its change in kinetic energy.
Conservation of mechanical energy — KE + PE is constant when only conservative forces do work. The condition is what makes the statement true, and omitting it is what loses the point.
Impulse–momentum theorem — J = FΔt = Δp = mv_f − mv_i. On a force–time graph, the impulse is the area under the curve.
Elastic vs inelastic collision — Both conserve momentum. Elastic conserves KE; inelastic does not. Perfectly inelastic → objects stick.
Centripetal acceleration and force — a_c = v²/r toward center; F_c = mv²/r. It is a net-force requirement, not a new force.
Hooke's law and spring PE — F = −kx (restoring); elastic PE = ½kx². k = spring constant (N/m).
Conditions for static equilibrium — ΣF = 0 AND Στ = 0. Torque τ = rF sinθ.
SHM period (pendulum & spring) — Pendulum: T = 2π√(L/g). Spring: T = 2π√(m/k). Period independent of amplitude.
Newton's third law — Forces come in equal and opposite pairs acting on DIFFERENT objects. The two never cancel, because they are not on the same body — which is why a horse can pull a cart.
Displacement vs. distance — Displacement is the signed change in position, Δx = x_f − x_i (a vector). Distance is the total path length traveled (a scalar) and is never negative.
Slope and area on a v–t graph — Slope of a velocity–time graph = acceleration; signed area between the curve and the time axis = displacement.
Key idea of projectile motion — Horizontal and vertical motions are independent: a_x = 0 with constant v_x, while a_y = −g. The two axes share only the time of flight.
Newton’s second law — ΣF = ma. Acceleration points along the net force and is inversely proportional to inertial mass.
Newton’s third-law pair — Two forces equal in magnitude, opposite in direction, of the same type, acting on different objects. They never cancel on a single free-body diagram.
Static vs. kinetic friction — Static friction adjusts up to a maximum μsN to prevent sliding; kinetic friction has fixed magnitude μkN and opposes relative sliding. Usually μs > μk.
Centripetal acceleration — a_c = v²/r directed toward the center of the circular path, caused by whatever real force points inward — tension, friction, gravity, or the normal force.
Newton’s law of universal gravitation — F = Gm₁m₂/r², attractive and along the line joining the centers. The field strength a distance r from mass M is g = GM/r².
Work done by a constant force — W = Fd cos θ, where θ is the angle between force and displacement. A force perpendicular to the displacement, such as the normal force on a slope, does zero work.
Power — P = W/Δt = Fv cos θ, measured in watts. At constant speed the drive force equals the resistive force, so P = Fv.
When is momentum conserved? — Whenever the net external force on the chosen system is zero, or negligible during a brief collision. Internal forces always cancel in third-law pairs.
Elastic vs. inelastic collision — Momentum is conserved in both; kinetic energy is conserved only in elastic collisions. A perfectly inelastic collision leaves the objects moving together and loses the maximum possible kinetic energy.