Non-Mendelian Inheritance
- Distinguish incomplete dominance from codominance in heterozygotes
- Predict blood-type offspring from the multiple-allele, codominant ABO system
- Explain how polygenic traits and sex-linked genes deviate from simple dominance
When the heterozygote looks different
Not every gene has a clean dominant-recessive relationship. In incomplete dominance, neither allele fully masks the other and the heterozygote shows a blended, intermediate phenotype — cross a red snapdragon (CᴿCᴿ) with a white one (CᵂCᵂ) and every offspring is pink (CᴿCᵂ). In codominance, both alleles are fully and separately expressed in the heterozygote — not blended. Roan cattle (with distinct red and white hairs side by side) and human AB blood are the classic cases. The tell: a mix means incomplete dominance; both at once means codominance.
Multiple alleles and ABO blood type
A gene can have more than two alleles in a population — though any one diploid person still carries only two. The ABO gene has three alleles: Iᴬ, Iᴮ, and i. Iᴬ and Iᴮ are codominant to each other, and both are dominant over the recessive i. This yields four blood types from six genotypes: type A (IᴬIᴬ or Iᴬi), type B (IᴮIᴮ or Iᴮi), type AB (IᴬIᴮ, both antigens shown — codominance), and type O (ii, no antigen).
Polygenic and sex-linked patterns
Polygenic inheritance means a single trait is controlled by many genes adding together — human skin color and height are set by several genes, producing smooth, continuous variation (a bell curve) rather than a few discrete categories. Sex-linked genes sit on the X chromosome. Because males are XY, they have only one copy of every X-linked gene, so a single recessive allele (like the one for red-green colorblindness) is expressed — there is no second X to mask it. This is why X-linked recessive conditions appear far more often in males than in females.
A woman with type A blood whose genotype is Iᴬi has children with a man of type B blood whose genotype is Iᴮi. What blood types can their children have, and in what ratio?
- 1.List each parent’s gametes. The mother (Iᴬi) makes ½ Iᴬ and ½ i. The father (Iᴮi) makes ½ Iᴮ and ½ i.
- 2.Combine every gamete pair in a Punnett square: IᴬIᴮ, Iᴬi, Iᴮi, and ii — each 1 of 4 boxes.
- 3.Translate genotypes to phenotypes: IᴬIᴮ = type AB (codominance), Iᴬi = type A, Iᴮi = type B, ii = type O.
In snapdragons, red (CᴿCᴿ) crossed with white (CᵂCᵂ) gives all pink (CᴿCᵂ) flowers. If two pink snapdragons are crossed (CᴿCᵂ × CᴿCᵂ), what phenotype ratio is expected in the offspring?
Do not merge incomplete dominance and codominance. Incomplete dominance blends (red + white → pink, a new intermediate). Codominance shows both fully (Iᴬ + Iᴮ → type AB, with both A and B antigens present, not a blend). The heterozygote phenotype is how you tell them apart.
A father with type O blood (ii) and a mother with type AB blood (IᴬIᴮ) have children. Which blood type is impossible among their children?
Red-green colorblindness is X-linked recessive. A carrier mother (XᴴXʰ) and a father with normal vision (XᴴY) have children. What fraction of their SONS are expected to be colorblind?
For sex-linked pedigree questions, remember the two shortcuts: a son inherits his single X-linked allele from his mother, and X-linked recessive traits are more common in males because their one X has no partner to mask a recessive allele.
Answer the 3 checkpoints as you read.
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