Parametric Arc Length
- Compute the arc length of a parametric curve
- Relate parametric arc length to the integral of speed
- Distinguish arc length (distance traveled) from displacement
Length of a parametric path
The arc length of a parametric curve from t = a to t = b sums the tiny hypotenuses √(dx² + dy²), now with both dx and dy expressed through t: L = ∫ₐᵇ √((dx/dt)² + (dy/dt)²) dt. This is the same Pythagorean idea as the y = f(x) arc-length formula, but symmetric in x and y because neither is privileged as the independent variable. It is literally the integral of the particle’s speed.
Arc length is distance traveled, not displacement
Because the integrand is the speed (always nonnegative), the parametric arc-length integral gives the total distance traveled along the path, even if the particle doubles back. This differs from displacement, the straight-line vector from start ⟨x(a), y(a)⟩ to end ⟨x(b), y(b)⟩. A particle that returns to its starting point has zero displacement but a positive arc length equal to the full path it walked.
Set up and evaluate the arc length of x = cos(t), y = sin(t) for t from 0 to π.
- 1.Differentiate: dx/dt = −sin(t), dy/dt = cos(t).
- 2.Form the integrand: √((−sin t)² + (cos t)²) = √(sin²t + cos²t) = √1 = 1.
- 3.The arc length integral becomes L = ∫₀^π 1 dt.
- 4.Evaluate: [t]₀^π = π.
Whenever the speed simplifies to a constant (as with a circle traced at unit speed), the arc-length integral collapses to speed × time. Always simplify the radicand before integrating — a Pythagorean identity often reduces it dramatically.
The arc length of a parametric curve from t = a to t = b is given by:
A particle travels along a parametric path and returns exactly to its starting point. Which statement is true?
Parametric arc length and "total distance traveled" are the same integral, ∫√((dx/dt)² + (dy/dt)²) dt. If a free-response question asks for the distance a particle travels in the plane, this is the formula — not the magnitude of the displacement vector.
Answer the 2 checkpoints as you read.
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