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Conservation of Momentum

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Isolated systems conserve momentum

If no net external force acts on a system, its total momentum stays constant. Internal forces — like two objects pushing on each other — come in equal-and-opposite Newton’s-third-law pairs, so they cancel within the system and cannot change the total. This holds through collisions, explosions, and recoil, and it does not care whether energy is conserved, which makes it enormously powerful.

Recoil and explosions from rest

When something starts at rest and then flies apart — a gun firing, a skater throwing a ball, a rocket expelling gas — the total momentum must stay zero. So the momenta of the pieces are equal in size and opposite in direction: the lighter piece flies off fast, the heavier piece recoils slowly. That is why a cannon lurches back only a little while the ball rockets forward.

Conservation of momentum
m₁v₁ + m₂v₂ = m₁v₁′ + m₂v₂′
Total momentum before = total momentum after. Keep signs consistent: opposite directions get opposite signs.
Worked example

A 200 kg cannon, initially at rest, fires a 4 kg cannonball forward at 50 m/s. Find the cannon’s recoil speed.

  1. 1.Before firing, total momentum is zero (everything at rest).
  2. 2.After firing it must still be zero: m_ball·v_ball + m_cannon·v_cannon = 0.
  3. 3.So 4 × 50 + 200 × v_cannon = 0 → 200 + 200·v_cannon = 0.
  4. 4.Solve: v_cannon = −200 ÷ 200 = −1 m/s (backward).
Answer: The cannon recoils at 1 m/s, opposite the ball
Watch out

Momentum is a vector — objects moving in opposite directions have opposite-sign momenta. Adding their magnitudes instead of accounting for direction is the classic conservation-of-momentum mistake.

Checkpoint

A 60 kg astronaut, floating at rest, throws a 3 kg wrench at 8 m/s. What is the astronaut’s recoil speed?

Checkpoint

Two skaters stand at rest and push off each other. Skater A (40 kg) glides away at 3 m/s. If skater B has a mass of 60 kg, what is B’s speed?

On the exam

For any "at rest, then flies apart" problem, set total momentum equal to zero. The pieces carry equal and opposite momenta, so the mass ratio is the inverse of the speed ratio — heavier means slower.

Answer the 2 checkpoints as you read.

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