Current, Resistance & Ohm’s Law
- Define electric current as the rate of charge flow and identify conventional current direction
- Relate voltage, current, and resistance through Ohm’s law
- Calculate electrical power dissipated in a resistor
Current is charge in motion
Electric current (I) is the rate at which charge flows past a point: I = Q/t, measured in amperes (1 A = 1 C·s⁻¹). By convention, current is drawn in the direction positive charge would move — from the + terminal of a battery around to the − terminal — even though in a metal wire it is really electrons drifting the opposite way. A battery supplies the voltage (potential difference) that pushes this charge around the circuit, like a pump maintaining pressure in a loop of pipe.
Resistance and Ohm’s law
Resistance (R) measures how strongly a component opposes current, in ohms (Ω). For many materials, current is proportional to the voltage across them — Ohm’s law, V = IR. A larger resistance means less current for the same voltage. Resistance grows with a wire’s length and shrinks with its cross-sectional area (a longer, thinner wire resists more), and depends on the material’s resistivity. Think of it as friction for flowing charge, turning electrical energy into heat.
A 12 V battery drives current through a 4.0 Ω resistor. Find the current and the power dissipated.
- 1.Solve Ohm’s law for current: I = V/R = 12 / 4.0 = 3.0 A.
- 2.Find power with P = IV = (3.0 A)(12 V) = 36 W.
- 3.Check with P = I²R = (3.0)²(4.0) = 9 × 4 = 36 W — the same.
The water analogy keeps the roles straight: voltage is the pump pressure, current is the flow rate, and resistance is a narrow constriction in the pipe. More pressure or a wider pipe → more flow.
A resistor has 12 V across it and carries a current of 3.0 A. What is its resistance?
A wire carries a steady current of 2.0 A for 10 s. How much charge flows past a point in the wire?
Know all three power formulas: P = IV, P = I²R, and P = V²/R. If a problem gives you resistance and voltage but not current, P = V²/R saves a step. They are algebraically identical via Ohm’s law.
Answer the 2 checkpoints as you read.
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