The Binomial Distribution
- Verify the four conditions (BINS) for a binomial setting
- Compute binomial probabilities and the mean and standard deviation
- Distinguish "exactly," "at most," and "at least" probability requests
The binomial setting: BINS
A count X is binomial when four conditions hold — remember BINS: Binary (each trial is a success or failure), Independent trials, a Number of trials n that is fixed in advance, and the Same probability of success p on every trial. X counts the successes in the n trials. If any condition fails — especially a fixed n — the model does not apply.
Computing binomial probabilities
The probability of exactly k successes multiplies three things: the number of arrangements of k successes among n trials, the probability of the k successes, and the probability of the n − k failures. Watch the phrasing: "at most k" means P(X ≤ k) (add up 0 through k), "at least k" means P(X ≥ k) (often easiest as 1 minus the smaller tail), and "exactly k" is a single term.
A free-throw shooter makes 80% of shots. In 10 independent attempts, find the expected number made and the standard deviation, then set up P(exactly 8 made).
- 1.Confirm binomial: binary (make/miss), independent shots, fixed n = 10, same p = 0.8. BINS holds.
- 2.Mean: μ = np = 10(0.8) = 8 made.
- 3.Standard deviation: σ = sqrt(np(1−p)) = sqrt(10 · 0.8 · 0.2) = sqrt(1.6) ≈ 1.26.
- 4.P(X = 8) = C(10,8)·(0.8)^8·(0.2)^2 = 45·(0.8)^8·(0.2)^2 ≈ 0.302.
Which situation is a valid binomial setting?
Read the boundary words carefully. "At least 8" is P(X ≥ 8) = P(8) + P(9) + P(10), while "at most 8" is P(X ≤ 8). Mixing these up is a frequent error; when in doubt, list exactly which values of X the phrase includes.
For a binomial random variable with n = 50 and p = 0.2, what is the standard deviation?
Answer the 2 checkpoints as you read.
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