Significance Tests for a Proportion
- State null and alternative hypotheses for a proportion
- Compute the one-sample z test statistic and p-value
- Make and interpret a decision in context
Hypotheses
A significance test weighs evidence against a claim. The null hypothesis H₀ states "no effect / the status quo," always as an equality: H₀: p = p₀. The alternative Hₐ states what we suspect: p < p₀, p > p₀, or p ≠ p₀. Hypotheses are always about the parameter p, never the statistic p-hat. Set them before looking at the data.
Test statistic and p-value
The z test statistic measures how many standard deviations p-hat falls from the null value p₀, using the null proportion in the standard error (because we assume H₀ true). The p-value is the probability, assuming H₀ is true, of getting a result as extreme or more extreme than observed. A small p-value means the data would be surprising if H₀ were true — evidence against H₀.
A company claims 90% of orders ship on time. An SRS of 200 orders finds 168 on time (p-hat = 0.84). Test at α = 0.05 whether the true on-time rate is below 90%.
- 1.Hypotheses: H₀: p = 0.90 vs. Hₐ: p < 0.90. Conditions: random, 10% (population > 2000), np₀ = 180 and n(1−p₀) = 20 both ≥ 10.
- 2.Standard error (using p₀): sqrt(0.90·0.10/200) = sqrt(0.00045) ≈ 0.0212.
- 3.Test statistic: z = (0.84 − 0.90)/0.0212 ≈ −2.83.
- 4.p-value: P(Z < −2.83) ≈ 0.0023, which is less than α = 0.05.
A significance test yields a p-value of 0.03. Using α = 0.05, what is the correct conclusion?
The p-value is not the probability that H₀ is true. It is the probability of data as extreme as observed assuming H₀ is true. And we never "accept" H₀ — we either "reject H₀" or "fail to reject H₀," because absence of evidence is not proof of no effect.
In the standard error for a one-sample z test for a proportion, which value should be used inside the square root?
Answer the 2 checkpoints as you read.
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