Geometric Optics unit test
A test on this unit alone, marked as a percentage and a letter grade — for the test your class is actually sitting, rather than for May. Answer everything, then submit once: seeing the answer to question 3 before attempting question 4 makes the final percentage meaningless.
Converging vs diverging lens
Predicting image type without calculating
Why the image of a half-covered lens is dimmer, not halved
Ray diagram rules for a lens
Apparent depth
Index of refraction
Fiber optics
Real image on a screen
Concave mirror
Magnification
Why a magnifying glass must be held close
Real vs virtual images
Short answer 1. Define or explain: Law of reflection
3 ptsShort answer 2. Define or explain: Thin lens equation
3 ptsShort answer 3. Define or explain: Sign conventions for lenses and mirrors
3 ptsShort answer 4. Define or explain: Total internal reflection
3 ptsFree response
10 ptsA converging lens has a focal length of 12 cm. An object 4.0 cm tall is placed 18 cm from the lens on the principal axis. (a) Calculate the image distance and the image height, and state whether the image is real or virtual and upright or inverted. (b) Describe the principal rays you would draw to locate this image. (c) The object is now moved to 6.0 cm from the lens. Calculate the new image distance and magnification, and describe the image. (d) Explain, using your results, how a converging lens is used as a magnifying glass. (e) A student covers the lower half of the lens with tape. Predict the effect on the image formed in part (a) and justify your prediction.