Equilibrium unit test
A test on this unit alone, marked as a percentage and a letter grade — for the test your class is actually sitting, rather than for May. Answer everything, then submit once: seeing the answer to question 3 before attempting question 4 makes the final percentage meaningless.
Effect of volume change
Le Châtelier's principle
Solubility product Ksp
ICE table
Reaction quotient Q
Common ion effect
Equilibrium constant K
Magnitude of K
Small-x approximation
Kc and Kp relationship
Effect of a catalyst on equilibrium
Effect of temperature on K
Short answer 1. Define or explain: pH effect on solubility
3 ptsShort answer 2. Define or explain: Dynamic equilibrium
3 ptsShort answer 3. Define or explain: Q vs K reasoning on a graph
3 ptsShort answer 4. Define or explain: Adding an inert gas at constant volume
3 ptsFree response
10 ptsSilver chloride is a sparingly soluble salt: AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq) Ksp = 1.8 × 10⁻¹⁰ at 25 °C
(a) Write the solubility-product expression for AgCl.
(b) Calculate the molar solubility of AgCl in pure water at 25 °C.
(c) Calculate the mass of AgCl that dissolves in 1.00 L of pure water at 25 °C.
(d) Calculate the molar solubility of AgCl in 0.100 M NaCl at 25 °C.
(e) Explain, in terms of Le Châtelier’s principle, why the solubility calculated in (d) differs from that in (b).
(f) Identify the name given to the effect described in part (e).
(g) A student mixes 50.0 mL of 2.0 × 10⁻⁴ M AgNO₃ with 50.0 mL of 2.0 × 10⁻⁴ M NaCl. Calculate the reaction quotient, Q, immediately after mixing.
(h) Using your answer to (g), predict whether a precipitate forms, and justify your prediction.
(i) The dissolution of AgCl is endothermic. Predict the effect of raising the temperature on the molar solubility of AgCl, and justify your prediction.
(j) Silver chloride dissolves readily in aqueous ammonia, forming the complex ion Ag(NH₃)₂⁺. Explain, in terms of equilibrium, why adding ammonia increases the solubility of AgCl.